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An object falls 16t^2 in t seconds.You drop a rock from a bridge that is 64 feet above the water. Will the rock hit the water in 2 seconds?

User FeRcHo
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Answer: Yes

Explanation:

To determine whether the rock will hit the water in 2 seconds, let's first analyze the motion of the falling object using the given information.

The equation for the displacement of an object in free fall is given by:

s = 16t^2

Where s represents the vertical displacement and t represents time.

In this case, the rock is dropped from a height of 64 feet above the water, so the equation becomes:

s = 64 - 16t^2

Here, s represents the displacement relative to the starting point, which is the height of the bridge.

To determine if the rock will hit the water in 2 seconds, we need to calculate the displacement of the rock at that time. Let's substitute t = 2 into the equation:

s = 64 - 16(2)^2

s = 64 - 16(4)

s = 64 - 64

s = 0

The result shows that at t = 2 seconds, the displacement of the rock is 0. This means that the rock has fallen exactly to the height of the water. Therefore, the rock will indeed hit the water in 2 seconds.

User Tarina
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