Answer:
- Water Appears with coefficient of 1
- 8 Electrons are transferred in this reaction.
Step-by-step explanation:
To balance the given equation under acidic conditions:
NO + ClO₃⁻ → NO₃⁻ + Cl₂
We can begin by balancing the atoms other than hydrogen and oxygen. Starting with nitrogen, we see that there is one nitrogen atom on the left side and one on the right side, so nitrogen is already balanced.
Next, let's balance the chlorine atoms. There is one chlorine atom on the left side and two chlorine atoms on the right side. To balance the chlorine, we need to add a coefficient of 2 in front of HClO₃.
NO + 2HClO₃ → NO₃⁻ + Cl₂
Now, let's balance the oxygen atoms. On the left side, there are three oxygen atoms from HClO₃ and one oxygen atom from NO, making a total of four oxygen atoms. On the right side, there are three oxygen atoms in NO₃⁻ and two oxygen atoms in Cl₂, making a total of five oxygen atoms. To balance the oxygen, we need to add a water molecule (H₂O) on the right side.
NO + 2HClO₃ → NO₃⁻ + Cl₂ + H₂O
Now, let's balance the hydrogen atoms. On the left side, there are six hydrogen atoms from HClO₃. On the right side, there are two hydrogen atoms from H₂O. To balance the hydrogen, we need to add four hydrogen ions (H⁺) on the left side.
NO + 2HClO₃ + 4H⁺ → NO₃⁻ + Cl₂ + H₂O
Now the equation is balanced under acidic conditions.
In the balanced equation, water appears as a product with a coefficient of 1.
So, water appears in the balanced equation as a product with a coefficient of 1.
To determine the number of electrons transferred in this reaction, we need to look at the change in oxidation states. The nitrogen atom in NO goes from an oxidation state of +2 to +5 in NO₃⁻, while the chlorine in ClO₃⁻ goes from an oxidation state of +5 to 0 in Cl₂.
Since the nitrogen atom gains 3 electrons and the chlorine atom gains 5 electrons, the total number of electrons transferred in this reaction is 3 + 5 = 8 electrons.