89.2k views
1 vote
Center:(4,-10)

Point of circle: (12, -10)

how do you use this information to write an equation?

User Rnorris
by
8.3k points

2 Answers

5 votes

Answer:

(x – 4)^2 + (y +10)^2 = 64

Explanation:

Recall that the formula for a circle is: (x – h)^2 + (y – k)^2 = r^2

1. Find the Radius (r): Luckily, we can count the distance since the coordinates have the same y-value. 12 - 4 = 8. So, r^2 = 8^2 = 64

2. Find h and k. These are the x and y coordinates of the center of the circle. So, h = 4, k = -10

3. Substitute the values in the equation:

(x – 4)^2 + (y – (-10))^2 = 8^2

(x – 4)^2 + (y +10)^2 = 64

User Thedp
by
8.1k points
1 vote

Answer:

(x -4)² +(y +10)² = 64

Explanation:

Given a circle through point (12, -10) with center (4, -10), you want its equation.

Equation

The equation of a circle with center (h, k) and radius r is ...

(x -h)² +(y -k)² = r²

Application

You are given the center (h, k) = (4, -10). You only need to know the radius to finish the equation. That will be the value of r that makes the equation true at the given point:

(x -4)² + (y +10)² = r²

(12 -4) + (-10 +10)² = r² . . . . . . with (x, y) = (12, -10), the point on the circle

8² + 0 = r²

The equation of the circle is (x -4)² +(y +10)² = 64.

__

Additional comment

The equation of a circle is essentially a statement of the distance formula. It is telling you that the circle consists of all points that are distance r from the center.

<95141404393>

User Aksadv
by
7.4k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories