98,063 views
5 votes
5 votes
In 2010, the population of a city was 193,000. From 2010 to 2015, the population grew by 6%. From 2015 to 2020, it fell by 3%. How much did the population decrease from 2015 to 2020, to the nearest 100 people?

User Ren
by
2.8k points

2 Answers

15 votes
15 votes

Final answer:

The population decreased by approximately 6,136 people from 2015 to 2020.

Step-by-step explanation:

To find the population decrease from 2015 to 2020, we need to calculate the difference between the populations in those years. Let's start by finding the population in 2015. From 2010 to 2015, the population grew by 6%. So, the population in 2015 would be:

Population in 2015 = Population in 2010 + (Growth rate * Population in 2010)

Population in 2015 = 193,000 + (0.06 * 193,000) = 193,000 + 11,580 = 204,580

Next, let's calculate the population in 2020. From 2015 to 2020, the population fell by 3%. So, the population in 2020 would be:

Population in 2020 = Population in 2015 - (Decrease rate * Population in 2015)

Population in 2020 = 204,580 - (0.03 * 204,580) = 204,580 - 6,137.4 ≈ 198,443.6

Finally, to find the decrease in population, we subtract the population in 2020 from the population in 2015:

Population decrease = Population in 2015 - Population in 2020

Population decrease = 204,580 - 198,443.6 ≈ 6,136.4

Therefore, the population decreased by approximately 6,136 people from 2015 to 2020.

User Richersoon
by
2.6k points
20 votes
20 votes

Answer:

6138

Step-by-step explanation:

First, we have to find the population of the city in 2015

6% = 0.06

193,000 times 0.06 = 11580 people increase

We know it is increasing, so we have to add them

193,000 + 11580 = 204580 people in 2015

Now let's find the 3% decrease

3% = 0.03

204580 times 0.03 = 6137.4

So, about 6138 people decrease from 2015 to 2020

User MrLeeh
by
3.1k points