Answer: Option C: 360 Joules
Step-by-step explanation:
First, let's convert the specific heat of aluminum from J/goC to cal/g. We can do this by using the conversion factor 1 J = 0.239 cal.
0.9 J/goC × 0.239 cal/J = 0.2151 cal/goC
Now, we can use the formula:
Heat gained or lost = mass × specific heat × change in temperature
We want to find the heat gained by 25g of aluminum when its temperature increases by 16°C. We'll plug in the values we know:
Heat gained = 25g × 0.2151 cal/goC × 16°C
Heat gained = 86.04 cal
Finally, we need to convert cal to J. We can use the conversion factor 1 cal = 4.184 J.
86.04 cal × 4.184 J/cal ≈ 360 J
Therefore, the answer is 360 joules. Option C is correct.