Answer:
Step-by-step explanation:
The amount of heat that must be added to heat 50 grams of water from 42.0° C to 100.0° C can be calculated using the specific heat capacity formula: Q = m*C*ΔT, where Q is the heat required, m is the mass of the water, C is the specific heat capacity of water, and ΔT is the temperature change.
Using the values given, we have:
Q = 50 g * 1 cal/g °C * (100.0°C - 42.0°C)
Q = 50 g * 1 cal/g °C * 58.0°C
Q = 2,900 calories
Therefore, the amount of heat that must be added to heat 50 grams of water from 42.0° C to 100.0° C is 2,900 calories. The answer is option (C).