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If 50 grams of water is to be heated from 42.0° C to 100.0° C to make a cup of tea, how much heat must be added?

Question 42 options:

15,200 calories


84 calories


2,900 calories


2,100 calories

1 Answer

6 votes

Answer:

Step-by-step explanation:

The amount of heat that must be added to heat 50 grams of water from 42.0° C to 100.0° C can be calculated using the specific heat capacity formula: Q = m*C*ΔT, where Q is the heat required, m is the mass of the water, C is the specific heat capacity of water, and ΔT is the temperature change.

Using the values given, we have:

Q = 50 g * 1 cal/g °C * (100.0°C - 42.0°C)

Q = 50 g * 1 cal/g °C * 58.0°C

Q = 2,900 calories

Therefore, the amount of heat that must be added to heat 50 grams of water from 42.0° C to 100.0° C is 2,900 calories. The answer is option (C).

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