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4. Solve for the missing side length. Round to the nearest tenth.

4. Solve for the missing side length. Round to the nearest tenth.-example-1

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Check the picture below.


6=x√(2)\implies \cfrac{6}{√(2)}=x\implies \cfrac{6}{√(2)}\cdot \cfrac{√(2)}{√(2)}=x\implies 3√(2)=x\implies 4.2\approx x

4. Solve for the missing side length. Round to the nearest tenth.-example-1
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