Question

A particle view of a sample of H2O2(aq) is shown above. The H2O2(aq) is titrated with KMnO4(aq), as represented by the equation below.

2 MnO4−(aq) + 5 H2O2(aq) + 6 H+(aq) → 2 Mn2+(aq) + 5 O2(g) + 8 H2O(l)

Which of the following particle views best represents the mixture when the titration is halfway to the equivalence point? (H2O molecules and H+ ions are not shown.)

Answer 1

At the halfway point of the titration, half of the MnO4¯ ions have been converted to Mn2+ ions. Therefore, the particle view that best represents the mixture at the halfway point would show half of the MnO4¯ ions converted to Mn2+ ions.

Step-by-step explanation:

In the given reaction, 2 MnO4¯(aq) + 5 H2O2(aq) + 6 H+(aq) → 2 Mn2+(aq) + 5 O2(g) + 8 H2O(l), at the halfway point to the equivalence point, half of the moles of H2O2 have reacted with the KMnO4 titrant. This means that half of the MnO4¯ ions have been converted to Mn2+ ions. Therefore, the particle view that best represents the mixture at the halfway point would show half of the MnO4¯ ions converted to Mn2+ ions.

Answer 2

The best particle view that represents the mixture halfway to the equivalence point in the titration of H₂O₂(aq) with KMnO₄(aq) is a mixture of Mn₂+(aq) ions and O₂(g) molecules. H₂O molecules and H+ ions are not shown.

Step-by-step explanation:

The best particle view that represents the mixture halfway to the equivalence point in the titration of H₂O₂ (aq) with KMnO₄ (aq) is a mixture of Mn₂ +(aq) ions and O2(g) molecules. At the halfway point, half of the H₂O₂ (aq) has reacted with the KMnO₄ (aq), resulting in the formation of Mn₂+(aq) ions and O2(g) molecules. The H₂O molecules and H+ ions are not shown in the particle view.

Example:

2 MnO₄−(aq) + 5 H₂O₂ (aq) + 6 H+(aq) → 2 Mn₂+(aq) + 5 O2(g) + 8 H₂O (l)