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Equation of circle in standard form, center of (12,-5) and radius of 9

User Guerino
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The standard form equation of a circle with center (h, k) and radius r is

(x - h)^2 + (y - k)^2 = r^2

Using the given information, we can substitute `h = 12`, `k = -5`, and `r = 9` into the equation to get:

(x - 12)^2 + (y - (-5))^2 = 9^2
(x - 12)^2 + (y + 5)^2 = 81

Therefore, the equation of the circle in standard form is `(x - 12)^2 + (y + 5)^2 = 81` and the center is `(12, -5)` with a radius of `9`.
User Dsifford
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