Question

A capacitor has charge 30nC and capacitance equal to 10nF (remember nano is 10^(-9)). What is the energy stored in this capacitor? Enter your answer in nJ (so, if your answer was "1.OnJ", you'd enter "1.0").

Answer 1

`U=450 \ nJ`

Step-by-step explanation:

`\boxed{\left\begin{array}{ccc}\text{\underline{Formula's used to find the Energy Stored in a Capacitor:}}\\\\\ U=(1)/(2)Q \Delta V= (1)/(2)C\Delta V^2=(Q^2)/(2C) \end{array}\right }`

Given:

`Q=30 \ nC \rightarrow 30 * 10 ^(-8) \ C\\\\C= 10 \ nF \rightarrow 10 *10^(-8) \ F`

Find:

`U=?? \ J`

`U=(Q^2)/(2C)\\\\\Longrightarrow U= ((30 * 10 ^(-8))^2)/(2(10 *10^(-8)))\\\\ \Longrightarrow U=4.5 *10^(-7) \ J\\\\\therefore \boxed{\boxed{U=450 \ nJ}}`

Thus, the energy stored in the capacitor is found.