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A flexible camping tank has a sample of butane gas at 12.3 atm and has volume of 8.5L . What will be the volume if the pressure is adjusted to 7.6 atm?

User Montooner
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We can use the combined gas law to solve this problem:

(P1 x V1) / T1 = (P2 x V2) / T2

where P1, V1, and T1 are the initial pressure, volume, and temperature, respectively, and P2 and V2 are the final pressure and volume, respectively.

Since the problem doesn't mention any changes in temperature, we can assume it remains constant. Therefore, we can simplify the equation to:

P1 x V1 = P2 x V2

Plugging in the given values, we get:

(12.3 atm) x (8.5 L) = (7.6 atm) x V2

Solving for V2, we get:

V2 = (12.3 atm x 8.5 L) / 7.6 atm

V2 = 13.77 L

Therefore, the volume will be 13.77 L when the pressure is adjusted to 7.6 atm.

User Ramiz
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