(2x^3y^-3)^2/16x^7y^-2 Fill in the value of the numerator of your final answer

asked Nov 10, 2024 235k views

4 votes

(2x^3y^-3)^2/16x^7y^-2

Fill in the value of the numerator of your final answer

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4 votes

Answer:

Explanation:

$((2x^3y^(-3))^2)/(16x^7y^(-2))\\ =(4x^6y^(-6))/(16x^7y^(-2))\\ =(1)/(4xy^4)$

Numerator = 1

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