165k views
3 votes
Just having a rough time with this please help. Thank you ​

Just having a rough time with this please help. Thank you ​-example-1

1 Answer

3 votes

Answer:

The formatting is a bit off but assuming that -x + 2y = 6 and -3x + y = -2 are the two separate equations, the solution to your system of equations is (2,4) or x = 2, y = 4.

Explanation:

Here is how you could solve this system of equations using the elimination method:

1. The first step is to find a variable you can eliminate, such as y.
-x+2y=6
-3x+y=-2

(multiply the second equation by -2)

−x+2y=6
6x-2y=4
This is your new set

2. Next, "add" your set together by lining it up and combining like terms.
-x+2y=6
+. 6x-2y=4
——————
5x = 10

3. Solve for x by dividing by 5
5x=10
10÷5=2
x=2

4. Now that you have your x, find y by substituting 2 for x in any of your original set's equations. We'll do the first equation, −x+2y=6.
−x+2y=6
-2+2y=6 ---> add 2 on both sides to remove -2
2y=8 ---> divide by 2 on both sides to remove the 2 from y
y=4

5. Set your answers up as an ordered pair like this ( ___ , ___ )
x=2 , y=4
(2, 4)

Hope this helps!

User WestonE
by
8.4k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories