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Just having a rough time with this please help. Thank you ​

Just having a rough time with this please help. Thank you ​-example-1

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3 votes

Answer:

The formatting is a bit off but assuming that -x + 2y = 6 and -3x + y = -2 are the two separate equations, the solution to your system of equations is (2,4) or x = 2, y = 4.

Explanation:

Here is how you could solve this system of equations using the elimination method:

1. The first step is to find a variable you can eliminate, such as y.
-x+2y=6
-3x+y=-2

(multiply the second equation by -2)

−x+2y=6
6x-2y=4
This is your new set

2. Next, "add" your set together by lining it up and combining like terms.
-x+2y=6
+. 6x-2y=4
——————
5x = 10

3. Solve for x by dividing by 5
5x=10
10÷5=2
x=2

4. Now that you have your x, find y by substituting 2 for x in any of your original set's equations. We'll do the first equation, −x+2y=6.
−x+2y=6
-2+2y=6 ---> add 2 on both sides to remove -2
2y=8 ---> divide by 2 on both sides to remove the 2 from y
y=4

5. Set your answers up as an ordered pair like this ( ___ , ___ )
x=2 , y=4
(2, 4)

Hope this helps!

User WestonE
by
8.4k points

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