Question

Aluminum and hydrogen chloride react to produce aluminum chloride and hydrogen gas. If 22.2 grams of aluminum and 35.2 grams of hydrogen chloride are used, what mass of aluminum chloride can be produced? How many liters of hydrogen gas would each produce? What is the limiting reactant? How much is left over?

Answer 1

Step-by-step explanation:

Answer and Explanation: 1

The first step to solve problems in stoichiometry is to establish the balanced chemical equation for the reaction as shown.

2

A

l

+

6

H

C

l

→

2

A

l

C

l

3

+

3

H

2

We are asked to determine the mass of HCl that completely reacts with the given amount of aluminum. To solve this, we need the following information on the molar mass of the reactants:

Al MW = 26.98 g/mol

HCl MW = 36.46 g/mol

Thus, converting the given amount of Al to grams of HCl, we get.

87.7

g

A

l

×

1

m

o

l

A

l

25.98

g

×

6

m

o

l

H

C

l

2

m

o

l

A

l

×

36.46

g

1

m

o

l

H

C

l

=

369

g

H

C

l