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Which situation could the probability distribution table represent?

Which situation could the probability distribution table represent?-example-1

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Answer: Choice A

There are 30 cards. Each card is labeled A, B, or C. Six of the cards are labeled A, 20 of the cards are labeled B and 4 of the cards are labeled C.

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Step-by-step explanation:

Let's rewrite each fraction in terms of the LCD 30

  • A: 1/5 = (1/5)*(6/6) = 6/30
  • B: 2/3 = (2/3)*(10/10) = 20/30
  • C: 2/15 = (2/15)*(2/2) = 4/30

Event A has probability 6/30, meaning there are 6 cards labeled "A" out of 30 cards total. Furthermore, we can see there are 20 labeled "B" and 4 labeled "C".

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