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Find the gradient of the curve y = 3x^4 - 2x^2 + 5x - 2 at the points (0, - 2) and (1,4)

User Kaf
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Answer: To find the gradient of a curve at a given point, we need to find the derivative of the function with respect to x and then evaluate it at the desired x-coordinate.

Given the function y = 3x^4 - 2x^2 + 5x - 2, we can find its derivative dy/dx as follows:

dy/dx = d/dx(3x^4) - d/dx(2x^2) + d/dx(5x) - d/dx(2)

Taking the derivative of each term:

dy/dx = 12x^3 - 4x + 5

Now, let's evaluate the derivative at the given points:

Point (0, -2):

Substituting x = 0 into the derivative:

dy/dx = 12(0)^3 - 4(0) + 5

dy/dx = 0 - 0 + 5

dy/dx = 5

Therefore, the gradient at (0, -2) is 5.

Point (1, 4):

Substituting x = 1 into the derivative:

dy/dx = 12(1)^3 - 4(1) + 5

dy/dx = 12 - 4 + 5

dy/dx = 13

Therefore, the gradient at (1, 4) is 13.

User Tbhaxor
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