Question

A boy whose weight is 600N runs up a fight of stairs 10m high in 12s. what is his average power​

Answer 1

`p = (w)/(t)`

`w = fdcosθ`

where p is power

w is work done

t is time in seconds

f is force

d is distance

f=600N

d=10

t=12

w=600 X 10

w=6000 Nm

p=6000/12

p=500 watts

Answer 2

Important Formulas:

`w=Fd`

`p=(w)/(t)`

work(measured in joules) = force(measured in newtons) * distance(measured in meters)

power(measured in watts) = work(measured in joules) / time(measured in seconds)

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Given:

`F=600N`

`d=10m`

`t=12s`

`p=?`

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Finding work:

`w=Fd`

`w=600*10`

`w=6000J`

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Finding power:

`p=(w)/(t)`

`p=(6000)/(12)`

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`\fbox{p = 500 watts}`