Question

in a triangle ABP base =3cm opp =2.8cm hyp =3.8cm find sin titan cos titan and tan titan please help me to solve this​

Answer 1

See below

Explanation:

`\sin\theta=\frac{\text{opposite}}{\text{hypotenuse}}=(2.8)/(3.8)\\\\\cos\theta=\frac{\text{adjacent (base)}}{\text{hypotenuse}}=(3)/(3.8)\\\\\tan\theta=\frac{\text{opposite}}{\text{adjacent (base)}}=(2.8)/(3)`