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When 4x2–8x–24=0 is written in the form (x–p)2=q, what is the value of q?

User Dharshana
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1 Answer

4 votes

Answer:

7

Explanation:

You want the constant q when 4x² -8x -24 = 0 is written as (x -p)² = q.

Rewrite

First, we can divide by 4:

x² -2x -6 = 0

To make the left side a perfect square, the constant there needs to be +1. Adding 7 to both sides will make it so:

x² -2x +1 = 7

(x -1)² = 7 . . . . . . . (p, q) = (1, 7)

The value of q is 7.

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Additional comment

The square of a binomial is ...

(x +b)² = x² +2bx +b²

The constant term (b²) is the square of half the coefficient of x. In the above equation, the coefficient of x is -2, so the constant needs to be ...

(-2/2)² = 1

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User Pompey
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