Question

Respond with steps please

`((6n)/(n+1))/(1+(2n-1)/(n+1) )`

Answer 1

Answer: 2

Explanation:

`((6n)/(n+1) )/(1+(2n-1)/(n+1) )` >find the common denominator for bottom

`=((6n)/(n+1) )/((1(n+1))/(n+1) +(2n-1)/(n+1) )` > common denominator on bottom, now add bottom

`=((6n)/(n+1) )/((n+1+2n-1)/(n+1) )` >simplify the bottom fraction

`=((6n)/(n+1) )/((3n)/(n+1) )` >When dividing fractions, (Keep-Change-Flip)

Keep the top, change problem to multplication,

Then flip the bottom fraction

`=(6n)/(n+1) * (n+1)/(3n)` >simplify, n+1 cancels, n cancels, 6 and 3 reduce

=2

Answer 2

Hello !

(6n/(n+1)) / (1 + (2n - 1) / (n+1))

= (6n/(n+1)) / ((n+1)/(n+1) + (2n - 1) / (n+1))

= (6n/(n+1)) / ((n+1+2n-1)/(n+1))

= (6n/(n+1)) / (3n/(n+1))

= 6n/3n

= 2