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((6n)/(n+1))/(1+(2n-1)/(n+1) )

2 Answers

2 votes

Answer: 2

Explanation:


((6n)/(n+1) )/(1+(2n-1)/(n+1) ) >find the common denominator for bottom


=((6n)/(n+1) )/((1(n+1))/(n+1) +(2n-1)/(n+1) ) > common denominator on bottom, now add bottom


=((6n)/(n+1) )/((n+1+2n-1)/(n+1) ) >simplify the bottom fraction


=((6n)/(n+1) )/((3n)/(n+1) ) >When dividing fractions, (Keep-Change-Flip)

Keep the top, change problem to multplication,

Then flip the bottom fraction


=(6n)/(n+1) * (n+1)/(3n) >simplify, n+1 cancels, n cancels, 6 and 3 reduce

=2

User Jisaacstone
by
8.6k points
4 votes

Hello !

(6n/(n+1)) / (1 + (2n - 1) / (n+1))

= (6n/(n+1)) / ((n+1)/(n+1) + (2n - 1) / (n+1))

= (6n/(n+1)) / ((n+1+2n-1)/(n+1))

= (6n/(n+1)) / (3n/(n+1))

= 6n/3n

= 2

User Katia
by
8.1k points

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