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From the top of a light tower 40m above sea level, a ship is observed at an angle of depression of 6 degrees. Calculate the distance of the ship from the foot of the light tower . Correct to 2 s.f

User Gregswiss
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2 Answers

1 vote

answers 4.2 cm

using the trigonometric ratios SohCahToa

tan6°= oppo/40cm

cross multiply to get opposite as 4.2 cm to 2sf

User Matthieun
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4 votes

Final answer:

The distance of the ship from the foot of the light tower is calculated using tangent function tan(6°) = 40/d, and it is approximately 380m when rounded to two significant figures.

Step-by-step explanation:

To calculate the distance of the ship from the foot of the light tower, given that the light tower is 40m above sea level and the angle of depression is 6 degrees, we can use trigonometry. The angle of depression is equal to the angle of elevation from the ship to the top of the tower, due to alternate interior angles created by a parallel line to the sea level and the line of sight from the tower. Since we have a right-angled triangle with the tower height as the opposite side and the angle of elevation as 6 degrees, we can use the tangent function.

Let d be the distance we want to find, which is the adjacent side of the triangle. We can write the following equation based on the tangent of the angle:

tan(6°) = opposite/adjacent = 40/d

Rearranging the equation, we get:

d = 40 / tan(6°)

Calculating this using a calculator and rounding to 2 significant figures:

d ≈ 380.52m, when rounding to 2 significant figures, d ≈ 380m.

User Jahid Shohel
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