Question

write the thermochemical equation that represents the exothermic reaction that occurs when two moles butane burns in excess oxygen. the molar enthalpy of combustion of butane is -2871 kj/mol

Answer 1

2C4H10(g) + 13O2(g) → 8CO2(g) + 10H2O(l) ΔH = -2871 kJ/mol

The enthalpy of combustion is the amount of heat released when one mole of a substance is burned in oxygen. In this case, the enthalpy of combustion of butane is -2871 kJ/mol, which means that 2871 kJ of heat is released when two moles of butane are burned in oxygen.