Answer:
One possible quadratic function that could represent f is:
f(x) = (x + 8)(x - 8)
This factorizes to:
f(x) = x^2 - 64
We can verify that this function has solutions of x = -8 and x = 8 by substituting them into the function and checking that the result is 0:
f(-8) = (-8)^2 - 64 = 0
f(8) = (8)^2 - 64 = 0
Therefore, the function f(x) = x^2 - 64 represents f, with solutions of x = -8 and x = 8.