The unit weight of the soil is 26.78 lb/ft^3 and the specific gravity of solids is 0.42.
How to solve
Property Value Unit
Void ratio 1.33 -
Water content 48% -
Density of water 62.4 lb/ft^3
The density of solids 25.98 lb/ft^3
Dry unit weight 17.55 lb/ft^3
Unit weight of soil 26.78 lb/ft^3
Specific gravity of solids 0.43 -
Step 1: Calculate the density of solids
The density of solids can be calculated using the following equation:
density solids = density water / (1 + void_ratio)
where:
density water is the density of water (62.4 lb/ft^3)
void ratio is the void ratio of the soil (1.33)
Substituting the values, we get:
density solids =
Step 2: Calculate the dry unit weight
The dry unit weight can be calculated using the following equation:
dry unit weight = density solids / (1 + water content decimal)
where:
density solids is the density of solids (25.98 lb/ft^3)
water content_decimal is the water content as a decimal (48% = 0.48)
Substituting the values, we get:
dry_unit_weight = 25.98 lb/ft^3 / (1 + 0.48) = 17.55 lb/ft^3
Step 3: Calculate the unit weight of the soil
The unit weight of the soil can be calculated using the following equation:
unit_weight = dry_unit_weight * (1 + water_content_decimal)
where:
dry_unit_weight is the dry unit weight of the soil (17.55 lb/ft^3)
water_content_decimal is the water content as a decimal (0.48)
Substituting the values, we get:
unit_weight = 17.55 lb/ft^3 * (1 + 0.48) = 26.78 lb/ft^3
Step 4: Calculate the specific gravity of solids
The specific gravity of solids can be calculated using the following equation:
specific gravity = density solids / density water
where:
density solids is the density of solids (25.98 lb/ft^3)
density water is the density of water (62.4 lb/ft^3)
Substituting the values, we get:
specific gravity = 25.98 lb/ft^3 / 62.4 lb/ft^3 = 0.42
Therefore, the unit weight of the soil is 26.78 lb/ft^3 and the specific gravity of solids is 0.42.