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Find the length of side x to the nearest tenth.

Find the length of side x to the nearest tenth.-example-1
User Tiandra
by
8.3k points

2 Answers

4 votes

Answer:

= 10.4

Explanation:

Here given is the right-angled triangle

For angle: = 60º

Perpendicular: = 9

Hypotenuse: =

Now using the trigonometry formula:

= /

sin 60º = 9/

3√2 = 9/

= 18/3√

= 10.4(rounded to the nearest tenth)

Therefore required length is = 10.4

User Arnaud Nelissen
by
7.8k points
4 votes

Answer: 7.8

Step-by-step explanation: Identify the triangle as a 45-45-90 triangle.

Recognize that the sides of a 45-45-90 triangle are in a ratio of 1:1:√2.

Find the length of the hypotenuse of the triangle. In this case, the hypotenuse is 11 units.

Divide the length of the hypotenuse by √2 to find the length of the side opposite the 45-degree angle. In this case, the length of side x is 11/√2 = 7.77 units.

Round the length of side x to the nearest tenth. In this case, the length of side x is 7.8 units.

User Anupriya
by
7.9k points

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