Final answer:
The area under the t-distribution with 10 degrees of freedom to the right of t=2.32 is larger than the area under the standard normal distribution to the right of z=2.32, because the t-distribution has heavier tails than the z-distribution.
Step-by-step explanation:
The question pertains to comparing the areas under two different probability distributions to the right of a specified value. More specifically, we need to determine which is larger: the area under the t-distribution with 10 degrees of freedom to the right of t=2.32, or the area under the standard normal distribution (also known as the z-distribution) to the right of z=2.32.
The area under the normal curve for any value can be found using a z-table, which gives us the cumulative area to the left of a specific z-score. To find the area to the right, we subtract this value from 1. However, because the t-distribution has heavier tails than the standard normal distribution, for the same t or z value the area to the right (or the p-value) is larger for a t-distribution with finite degrees of freedom compared to the standard normal distribution. Hence the area to the right of 2.32 in the t-distribution with 10 df will be larger than the area to the right of 2.32 in the standard z-distribution.
It's also noteworthy that as the degrees of freedom increase, the t-distribution approaches the standard normal distribution. Therefore, the difference in areas for a given t or z value will diminish as the number of degrees of freedom increases.