Final answer:
The expression for the minimum spread ax of impacts at the bull's-eye, taking into consideration the uncertainties in the location of the release point and the horizontal component of speed, is ax = h/4m√(2gyo).
Step-by-step explanation:
In order to derive an expression for the minimum spread ax of impacts at the bull's-eye, we need to consider the uncertainty in the location of the release point (ax) and the uncertainty in the horizontal component of the speed (av). Assuming that the bull's-eye is located a distance yo below the release point, the minimum spread ax can be calculated using the uncertainty principle.
Using the uncertainty principle, we know that the uncertainty in position (ax) and the uncertainty in momentum (av) are related by the equation AxAp ≥ h/4. Rearranging this equation, we can solve for the uncertainty in position Ax = h/4Av. Substituting Av = m√(2gyo), where m is the mass of the bb, g is the acceleration due to gravity, and yo is the vertical distance between the release point and the bull's-eye, we get Ax = h/4m√(2gyo). Therefore, the expression for the minimum spread ax is ax = h/4m√(2gyo).