Question

What is the value of x in the equation below?1+2e^x+1=9a). x=log4-1b) x=log4c). x=Ln4-1d). x=ln4

Answer 1

Answer: Ln(4) - 1

The -1 part is not inside the natural log.

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Work Shown:

1 + 2*e^(x+1) = 9

2*e^(x+1) = 9-1

2*e^(x+1) = 8

e^(x+1) = 8/2

e^(x+1) = 4

x+1 = Ln(4)

x = Ln(4) - 1