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Use limits to find the area of the region between the graph of y=x³+1

and the x-axis on the interval [2, 4], or f(x³ + 1) dx

User Geekkoz
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1 Answer

1 vote

Answer:

62

Step-by-step explanation:

Find the area of the region bounded the graph of y=x³+1 and the x-axis over the interval [2,4].


\text{\underline{Set up:}}\\\\\Longrightarrow \boxed{\int\limits^4_2 {x^3+1} \, dx}


\text{Now solving...}\\\\\Longrightarrow \int\limits^4_2 {x^3+1} \, dx\\\\\Longrightarrow (1)/(4)x^4+x \Big]\limits^4_2\\\\\Longrightarrow [(1)/(4)(4)^4+(4)]-[(1)/(4)(2)^4+(2)]\\\\\Longrightarrow [68]-[6]\\\\\Longrightarrow \boxed{\boxed{=62}}

Thus, the problem is solved.

User Stefano Bagnara
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