Question

object i, shown above, has a charge of 3*10^-6 coulomb and a mass of 0.0025 kilogram. what is the electric potential at point p, 0.3 meter from object i?

Answer 1

`\huge\boxed{\sf V = 90,000 \ v}`

Step-by-step explanation:

Given data:

Charge = Q = 3 × 10⁻⁶ C

Distance = r = 0.3 m

k = 9 × 10⁹ Nm/C²

Required:

Electric Potential = V = ?

Formula:

`\displaystyle V = (kQ)/(r)`

Solution:

Put the given data in the above formula.

`\displaystyle V=((9 * 10^9)(3 * 10^(-6)))/(0.3) \\\\V=(27 * 10^3)/(0.3) \\\\V= 90 * 10^3\\\\V = 90,000 \ v\\\\\rule[225]{225}{2}`