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A toaster oven is rated at 1600 W for operation at 120 V, 60 Hz. a. What is the resistance of the oven heater element? b. What is the peak current through it? c. What is the peak power dissipated by the oven?

User Zev
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Final answer:

a) The resistance of the oven heater element is 9 ohms. b) The peak current through the oven heater element is 13.33A. c) The peak power dissipated by the oven is 1600W.

Step-by-step explanation:

a) To find the resistance of the oven heater element, we can use Ohm's Law: R = V/I, where R is the resistance, V is the voltage, and I is the current. Since the toaster oven is operating at 120V, we can calculate the resistance using the power formula P = IV. Rearranging the formula to solve for resistance, we have R = V²/P. Substituting the given values, we get R = (120V)²/1600W = 9 ohms.

b) The peak current can be calculated using the formula P = IV, where P is the power and I is the current. Rearranging the formula to solve for current, we have I = P/V. Substituting the given values, we have I = 1600W/120V = 13.33A. Therefore, the peak current through the oven heater element is 13.33A.

c) The peak power dissipated by the oven can be calculated using the formula P = IV. Substituting the given values, we have P = 13.33A x 120V = 1600W. Therefore, the peak power dissipated by the oven is 1600W.

User Namuol
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