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find the specific heat (in joule/mole k) of a gas kept at constant volume when it takes 8 x 104 j of heat to raise the temperature of 5 moles of the gas from 62 to 269 degrees c.

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Answer:


C=77.3 (Joule)/(mole* K)

Step-by-step explanation:

Given:

Heat input:
Q=8* 10^4 J

no. of moles:
n=5 mols

change in temperature:
T=T_f-T_i=269-62=207

Since the gas is held at constant volume, we don't have to worry about any heat going into changing the volume.

We can find a formula to the specific heat capacity of the gas through the equation of heat:


Q=nCT

(The original equation is
Q=mCT, but you since he asked for the unit to be Joule/mol x K, we can replace the mass with the number of mols)

by substitution, we get:


C=(Q)/(nT)=(8* 10^4)/(5* 207)\\ \\ C=77.3 (Joule)/(mole* K)

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