Question

find the specific heat (in joule/mole k) of a gas kept at constant volume when it takes 8 x 104 j of heat to raise the temperature of 5 moles of the gas from 62 to 269 degrees c.

Answer 1

`C=77.3 (Joule)/(mole* K)`

Step-by-step explanation:

Given:

Heat input:
`Q=8* 10^4 J`

no. of moles:
`n=5 mols`

change in temperature:
`T=T_f-T_i=269-62=207`

Since the gas is held at constant volume, we don't have to worry about any heat going into changing the volume.

We can find a formula to the specific heat capacity of the gas through the equation of heat:

`Q=nCT`

(The original equation is
`Q=mCT`, but you since he asked for the unit to be Joule/mol x K, we can replace the mass with the number of mols)

by substitution, we get:

`C=(Q)/(nT)=(8* 10^4)/(5* 207)\\ \\ C=77.3 (Joule)/(mole* K)`