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a 2.00 m long string transmits waves at 12.9 m/s what is the fundamental frequency for standing waves in this string

User Mizlul
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1 Answer

6 votes

Answer:


\huge\boxed{\sf f=3.225 \ Hz}

Step-by-step explanation:

Given data:

Length = L = 2 m

Speed = v = 12.9 m/s

Required:

Fundamental frequency = f = ?

Formula:


\displaystyle f =(v)/(2L)

Solution:

Put the given data in the above formula.


\displaystyle f = (12.9)/(2(2)) \\\\f=(12.9)/(4) \\\\f=3.225 \ Hz\\\\\rule[225]{225}{2}

User Mike Hanafey
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