Answer: The ball lands 5 seconds after it was thrown.
Step-by-step explanation:
The basketball hits the ground when h = 0. So, we set h = 0 in the equation and solve for t:
0 = -32t² + 160t
This is a quadratic equation in the form of at² + bt + c = 0. We can factor out a common factor of -32t:
0 = -32(t - 5)
Setting each factor equal to zero gives the solutions to the equation:
-32t = 0 => t = 0
t - 5 = 0 => t = 5
So, the times when the ball is on the ground are t = 0 (when it was first thrown) and t = 5 seconds (when it lands). Therefore, the ball lands 5 seconds after it was thrown.