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The volume of a gas inside a balloon is 436.1 mL when the temperature is 298 K. At the same pressure, what is the volume of the balloon in mLwhen the temperature decreases by 20C?

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Answer:

We can solve this problem using the combined gas law, which relates the initial and final volumes and temperatures of a gas:

(P1 x V1) / T1 = (P2 x V2) / T2

where P is the pressure, V is the volume, and T is the temperature.

Let's convert the initial volume to liters and the initial temperature to Kelvin:

V1 = 436.1 mL = 0.4361 L

T1 = 298 K

Next, let's convert the final temperature to Kelvin:

T2 = (20°C + 273.15) K = 293.15 K

Finally, let's plug in the given pressures and solve for V2:

P1 = P2

V2 = (P1 x V1 x T2) / (T1 x P2)

V2 = (4.45 atm x 0.4361 L x 293.15 K) / (298 K x 0.289 atm)

V2 ≈ 0.699 L

V2 ≈ 699 mL

Therefore, the volume of the gas inside the balloon is approximately 699 mL when the temperature decreases by 20°C.

Step-by-step explanation:

User Banex
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