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When csc(0)sin(0) is simplified, what is the result?

User Xapadoan
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1 Answer

5 votes

Answer:

csc θ * sin θ

Simplified using trig identities:

csc (x) = 1/sin(x)

so, csc (0) = 1/sin(0)

1/sin(0) * sin (0), the result will be sin(0) / sin (0) which is equal to 1.

Therefore, the answer is 1.

Explanation:

Expression in sin θ and cos θ below

4cos ec^2 2θ as 2 / 2 (4 sin θ cos θ )^2

or

cos ec^2 θ as 1 / sin ^2 θ

. Accept terms like

cos ec^2 θ = 1 +cot^2 θ =1 + cot^2 θ /sin^2 θ

User Chase Henslee
by
8.0k points

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