Question

How many L of 4.0 M solution can be made with 132g of NaCI ?

A)9.02L
B)9.02ml
C)0.9L

Answer 1

0.430 Litre

Step-by-step explanation:

The first thing that you need to do here is to convert the mass of lithium bromide to moles by using the compound's molar mass.
`100g (1 moleNaCl)/(58.5g) = 1.71 moles of NaCl`

Now, the molarity of the solution is simply a measure of the number of moles of solute, which in your case is NaCl, present for every 1.00 L of the solution.

In order to have a 4.00-M solution of NaCl, you need to have 4.00 moles of NaCl for every 1.00 L of this solution.

You know that your sample contains 1.71 moles of NaCl, so you can use the molarity of the solution as a conversion factor to determine how many liters of this solution can be made.

`1.71 mole NaCl ( 1 L Solution)/(4 mole NaCl) = 0.43 L solution`.

Answer 2

To determine how many liters of a 4.0 M NaCl solution can be made with 132g of NaCl, convert grams to moles using the molar mass, then divide by the molarity. The calculation yields approximately 0.56 liters of solution.

The student is asking how many liters of a 4.0 M NaCl solution can be made with 132g of NaCl. To determine this, we first convert from grams to moles of NaCl using the molar mass of NaCl (58.44 g/mol) as a unit conversion factor. By dividing 132g by 58.44 g/mol, we obtain approximately 2.26 moles of NaCl.

Knowing that Molarity (M) is defined as moles of solute per liter of solution (mol/L), we can rearrange the equation M = moles/L to solve for the volume (L) by dividing the moles of NaCl by the molarity. So, volume = 2.26 moles / 4.0 M, which gives us a final volume of approximately 0.565 liters or 0.56 liters when rounded to two significant figures.

Thus, with 132g of NaCl, one can make approximately 0.56 liters of a 4.0 M NaCl solution, which is closest to option C) 0.9L, assuming the question intended to offer a nearly correct choice.