Question

1. How many grams of carbon dioxide are produced when 25.0 g of propane, C,H, is burned with 75.0 g of Oxygen?

Answer 1

61.9 g C3H8

Step-by-step explanation:

First write and balance equation

C3H8 + 5O2 -> 3CO2 + 4H2O

Next find the limiting reactant

25.0g propane/ 44.097 g propane = 0.567 mol propane

(75.0gO2)(1mol C3H8)/ (32g)(5mol O2)= 0.468 mol propane

Since O2 is the limiting reactant now we can find the mass of CO2

(75.0g O2)(1 mol O2)( 3 mol CO2)(44.01 g CO2)/(32g O2)(5 mol O2)( 1 mol CO2) =61.9g CO2