Question

Balance the following redox reaction if it occurs in acidic solution. What are the coefficients in front of Cd and H+ in the balanced reaction? Cd2+(aq) + NH4+(aq) → Cd(s) + NO3(aq) Cd = 1, H+ = 6 Cd = 3, H+ = 4 O Cd = 4, H+ = 10 O Cd = 1, H+ = 2 O Cd = 2, H+ = 3

Answer 1

To balance the redox reaction in acidic solution, we need to assign oxidation states to each element and then balance the atoms and charges in the reaction.

The To balance the redox reaction in acidic solution, we need to assign oxidation states to each element and then balance the atoms and charges in the reaction.

The oxidation state of Cd changes from +2 on the left side to 0 on the right side (since it is reduced from Cd2+ to Cd). The oxidation state of N changes from -3 on the left side to +5 on the right side (since it is oxidized from NH4+ to NO3-).

Now, let's balance the reaction step by step:

Balance all atoms except hydrogen and oxygen:

Cd2+(aq) + NH4+(aq) → Cd(s) + NO3-(aq)

Balance oxygen atoms by adding H2O molecules:

Cd2+(aq) + NH4+(aq) → Cd(s) + NO3-(aq) + H2O(l)

Balance hydrogen atoms by adding H+ ions:

Cd2+(aq) + NH4+(aq) + 6H+(aq) → Cd(s) + NO3-(aq) + H2O(l)

Finally, the balanced coefficients in front of Cd and H+ are:

Cd = 1, H+ = 6

Therefore, the correct answer is: Cd = 1, H+ = 6.of Cd changes from +2 on the left side to 0 on the right side (since it is reduced from Cd2+ to Cd). The oxidation state of N changes from -3 on the left side to +5 on the right side (since it is oxidized from NH4+ to NO3-).

Now, let's balance the reaction step by step:

Balance all atoms except hydrogen and oxygen:

Cd2+(aq) + NH4+(aq) → Cd(s) + NO3-(aq)

Balance oxygen atoms by adding H2O molecules:

Cd2+(aq) + NH4+(aq) → Cd(s) + NO3-(aq) + H2O(l)

Balance hydrogen atoms by adding H+ ions:

Cd2+(aq) + NH4+(aq) + 6H+(aq) → Cd(s) + NO3-(aq) + H2O(l)

Finally, the balanced coefficients in front of Cd and H+ are:

Cd = 1, H+ = 6

Answer 2

To balance the redox reaction Cd2+(aq) + NH4+(aq) → Cd(s) + NO3-(aq) in acidic solution, the coefficients in front of Cd and H+ are Cd = 1, H+ = 8.

Step-by-step explanation:

In order to balance the redox reaction in an acidic solution, we first need to assign oxidation numbers to each element in the reaction. This gives us:

1) Cd2+(aq) + NH4+(aq) → Cd(s) + NO3-(aq)

Next, we balance the atoms other than hydrogen (H) and oxygen (O). This gives us:

1) Cd2+(aq) + 2NH4+(aq) → Cd(s) + 2NO3-(aq)

Now, we balance the oxygen atoms by adding water (H2O) molecules. This gives us:

1) Cd2+(aq) + 2NH4+(aq) → Cd(s) + 2NO3-(aq) + H2O(l)

Finally, we balance the hydrogen ions (H+) by adding hydrogen ions to the opposite side of the reaction. This gives us:

1) Cd2+(aq) + 2NH4+(aq) + 8H+(aq) → Cd(s) + 2NO3-(aq) + H2O(l)

Therefore, the coefficients in front of Cd and H+ in the balanced reaction are:

Cd = 1, H+ = 8