To balance the redox reaction in acidic solution, we need to assign oxidation states to each element and then balance the atoms and charges in the reaction.
The To balance the redox reaction in acidic solution, we need to assign oxidation states to each element and then balance the atoms and charges in the reaction.
The oxidation state of Cd changes from +2 on the left side to 0 on the right side (since it is reduced from Cd2+ to Cd). The oxidation state of N changes from -3 on the left side to +5 on the right side (since it is oxidized from NH4+ to NO3-).
Now, let's balance the reaction step by step:
Balance all atoms except hydrogen and oxygen:
Cd2+(aq) + NH4+(aq) → Cd(s) + NO3-(aq)
Balance oxygen atoms by adding H2O molecules:
Cd2+(aq) + NH4+(aq) → Cd(s) + NO3-(aq) + H2O(l)
Balance hydrogen atoms by adding H+ ions:
Cd2+(aq) + NH4+(aq) + 6H+(aq) → Cd(s) + NO3-(aq) + H2O(l)
Finally, the balanced coefficients in front of Cd and H+ are:
Cd = 1, H+ = 6
Therefore, the correct answer is: Cd = 1, H+ = 6.of Cd changes from +2 on the left side to 0 on the right side (since it is reduced from Cd2+ to Cd). The oxidation state of N changes from -3 on the left side to +5 on the right side (since it is oxidized from NH4+ to NO3-).
Now, let's balance the reaction step by step:
Balance all atoms except hydrogen and oxygen:
Cd2+(aq) + NH4+(aq) → Cd(s) + NO3-(aq)
Balance oxygen atoms by adding H2O molecules:
Cd2+(aq) + NH4+(aq) → Cd(s) + NO3-(aq) + H2O(l)
Balance hydrogen atoms by adding H+ ions:
Cd2+(aq) + NH4+(aq) + 6H+(aq) → Cd(s) + NO3-(aq) + H2O(l)
Finally, the balanced coefficients in front of Cd and H+ are:
Cd = 1, H+ = 6