The charge on each plate of the 0.45 μF capacitor connected to a 7.5 V battery is approximately 3.4 μC.
Determine the charge of the capacitor?
The charge on a capacitor can be calculated using the formula Q = CV, where Q is the charge, C is the capacitance, and V is the voltage across the capacitor. In this case, the capacitance is 0.45 μF and the voltage is 7.5 V.
Substituting these values into the formula, we have:
Q = (0.45 μF) × (7.5 V)
= 3.375 μC
Rounding the answer to two significant figures gives approximately 3.4 μC.
Therefore, each plate of the capacitor has a charge of approximately 3.4 μC when connected to the 7.5 V battery.
Complete question here:
A 0.45−μF capacitor is connected to a 7.5−V battery. How much charge is on each plate of the capacitor? Express your answer using two significant figures.