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Suppose that 3.65 g of HCl are dissolved in 10.0 L of water.

What is the value of [H+]?
Show that [OH-] is 1.00 x 10-12 M.

User Ifoukarakis
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1 Answer

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Step-by-step explanation:

The value of [H+] can be calculated using the concentration of the HCl solution and the balanced chemical equation for the dissociation of HCl in water:

HCl (aq) + H2O (l) → H3O+ (aq) + Cl- (aq)

The concentration of HCl is 3.65 g / (36.5 g/mol) = 0.1 M

The concentration of H+ ions in the solution can be calculated using the concentration of HCl and the stoichiometry of the dissociation reaction:

[H+] = 0.1 M x (1 mol H+ / 1 mol HCl) = 0.1 M

To show that [OH-] is 1.00 x 10-12 M, we can use the relationship between [H+] and [OH-] in aqueous solutions, which is given by the ion product constant for water (Kw):

Kw = [H+] [OH-] = 1.00 x 10-14

Substituting the value of [H+] that we calculated above, we can solve for [OH-]:

[OH-] = Kw / [H+] = (1.00 x 10-14) / (0.1 M) = 1.00 x 10-12 M

Therefore, the concentration of OH- ions in the solution is 1.00 x 10-12 M.

User Quisse
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