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√2w+5-3

2w-4
2. Evaluate
(A) 0
(B) co
(C) -4
(D)
(E) The limit does not exist.
3. If f(x)= (5x + 2), find f'(x).
(A) f(x) =
35(5x + 2)
(B) f (x) =
35(5x + 2)
(C) f (x)= 35(5x + 2) cos cos (5x + 2)
(D) f (x)=- 35(5x + 2) sin sin (5x + 2)
(E) f(x)=- 35(5x + 2)

User Petrona
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1 Answer

1 vote

Answer:

2. To evaluate the limit, we need to factor the numerator and the denominator of the fraction first:

√(2w+5)-3 / (2w-4) = [√(2w+5)-3] / [2(w-2)]

Now, we can see that the denominator becomes zero when w = 2. So, we need to check the limit separately for the left-hand and right-hand limits.

For the left-hand limit, as w approaches 2 from the left, the numerator approaches -3, and the denominator approaches a negative number very close to zero. So, the limit goes to negative infinity.

For the right-hand limit, as w approaches 2 from the right, the numerator approaches -3, and the denominator approaches a positive number very close to zero. So, the limit goes to positive infinity.

Since the left-hand limit and the right-hand limit are not equal, the limit does not exist.

Therefore, the answer is (E) The limit does not exist.

3. The derivative of f(x) = 5x + 2 is given by the formula:

f'(x) = d/dx (5x + 2) = 5

Therefore, the answer is (E) f(x)=- 35(5x + 2).

User Robert Pounder
by
8.9k points

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