Question

A particle of mass m travels at a speed of v=0.28c. at what speed will its momentum be doubled?

Answer 1

We know that momentum (p) is given by:

p = mv

If we want to double the momentum, we need to find the velocity (v') that satisfies the equation:

2p = m v'

We can rearrange this equation to solve for v':

v' = (2p)/m

Now, we need to find the momentum (p) of the particle traveling at speed v:

p = mv = m(0.28c)

We can substitute this expression for p into the equation for v':

v' = (2p)/m = (2m(0.28c))/m = 0.56c

Therefore, the particle needs to travel at a speed of 0.56c in order for its momentum to be doubled.