Question

What’s the answer to the question I’m confused

Answer 1

let's move like the crab, backwards, let's get hmmm EF first

`\begin{array}{llll} \textit{using the pythagorean theorem} \\\\ a^2+o^2=c^2\implies o=√(c^2 - a^2) \end{array} \qquad \begin{cases} c=\stackrel{hypotenuse}{17}\\ a=\stackrel{adjacent}{10}\\ o=\stackrel{opposite}{EF} \end{cases} \\\\\\ EF=√( 17^2 - 10^2)\implies EF=√( 189 )\implies EF\approx 13.7 \\\\[-0.35em] ~\dotfill`

`\sin( F )=\cfrac{\stackrel{opposite}{10}}{\underset{hypotenuse}{17}} \implies \sin^(-1)(~~\sin( F )~~) =\sin^(-1)\left( \cfrac{10}{17} \right) \\\\\\ F =\sin^(-1)\left( \cfrac{10}{17} \right)\implies F \approx 36^o \\\\[-0.35em] ~\dotfill\\\\ \cos(D )=\cfrac{\stackrel{adjacent}{10}}{\underset{hypotenuse}{17}} \implies \cos^(-1)(~~\cos( D )~~) =\cos^(-1)\left( \cfrac{10}{17} \right) \\\\\\ D =\cos^(-1)\left( \cfrac{10}{17} \right)\implies D \approx 54^o`

Make sure your calculator is in Degree mode.