Question

List the following compounds in decreasing electronegativity difference. br2 hbr kbr

Answer 1

The electronegativity difference between two atoms is a measure of the polarity of a chemical bond. To determine the decreasing electronegativity difference, we compare the electronegativities of the elements in the compounds. The compounds can be listed in decreasing electronegativity difference as follows: KBr, HBr, Br2.

Step-by-step explanation:

The electronegativity difference between two atoms is a measure of the polarity of a chemical bond. It indicates the inequality in the sharing of electrons between the atoms. The larger the electronegativity difference, the more polar the bond. To determine the decreasing electronegativity difference among the compounds Br2, HBr, and KBr, we need to compare the electronegativities of the elements bromine and hydrogen, and the element bromine and potassium.

The electronegativity values of the elements are as follows:

• Bromine (Br): 2.96
• Hydrogen (H): 2.20
• Potassium (K): 0.82

Based on these values, we can calculate the electronegativity differences for the compounds:

• Br2: 2.96 - 2.96 = 0
• HBr: 2.96 - 2.20 = 0.76
• KBr: 2.96 - 0.82 = 2.14

Therefore, the compounds can be listed in decreasing electronegativity difference as follows: KBr, HBr, Br2.

Answer 2

In order of electronegativity is; HBr > KBr >
`Br_2`

The ability of an atom to draw an electron bonding pair into a chemical bond is measured by its electronegativity. This characteristic aids in the prediction of the kind of chemical bonds that form between atoms. It was Linus Pauling who first put forth the concept.

Atoms with higher electronegativity values tend to attract electrons more strongly, leading to an uneven distribution of charge in a covalent bond.

We know that the HBr has the greatest difference in electronegativity followed by KBr and
`Br_2` is the least.