Question

there are 15 patients in dr. ziglar's waiting room. dr. ziglar can see 6 patients before lunch. in how many different orders can dr. ziglar see 6 of the patients before lunch?

Answer 1

There are 360360 different orders in which Dr. Ziglar can see 6 patients before lunch.

Explanation:

This is a permutation problem since the order in which Dr. Ziglar sees the patients matters. We want to know in how many ways we can choose 6 patients out of 15 to see before lunch.

Using the permutation formula, we get:

P(15,6) = 15! / (15-6)! = 15 x 14 x 13 x 12 x 11 x 10 = 360360

Therefore, there are 360360 different orders in which Dr. Ziglar can see 6 patients before lunch.