Question

47.5 L of neon gas is heated from 22 °C to 158 °C. Calculate the final volume of the gas.

Answer 1

(47.5 L)/(22 °C + 273.15 K) = V2/(158 °C + 273.15 K)

V2 = (47.5 L)(431.15 K)/(295.15 K) = 64.7 L

Therefore, the final volume of the gas is 64.7 L.