49.7k views
2 votes
You have a standard deck of 52 cards. You draw one card. What is the probability that it is an even number or a club? (Hint: There are 4 suits, 13 cards of each suit, and 3 face cards of each suit.)

P(even U club)

options:

0.43

0.54

0.63

0.1

User Alesi
by
9.1k points

1 Answer

3 votes

Answer:

There are 20 cards in the deck that are either even or a club. There are 9 even-numbered cards (2, 4, 6, 8, 10, Jack, Queen, King, and Ace of spades) and 11 club cards (Ace, 2, 3, 4, 5, 6, 7, 8, 9, 10, and Jack of clubs).

However, the card 8 of clubs is both an even-numbered card and a club, and we don't want to count it twice. So, we subtract one from the total count to get 20 cards in total.

The probability of drawing an even number or a club is the number of favorable outcomes (i.e., drawing an even number or a club) divided by the total number of possible outcomes (i.e., drawing any card).

Therefore, the probability of drawing an even number or a club is:

P(even U club) = number of favorable outcomes / total number of possible outcomes

= 20/52

= 5/13

≈ 0.385

So, the closest option to the calculated probability is 0.43.

User Djcredo
by
7.4k points