Question

When a dehydrated patient is given an intravenous saline solution, this solution must be matched to the osmotic pressure of red blood cells, which is approximately 8.0 atm. To make such a solution, how many grams of NaCl should be added to 1.0 L of water? Note that 1 mol of NaCl dissociates to 2 mol of solute particles in solution. Assume the temperature of a human body is 37∘C. Express your answer in grams.

Answer 1

To make an intravenous saline solution that matches the osmotic pressure of red blood cells, calculate the molarity of NaCl needed in the solution and use the equation Osmotic Pressure = Molarity × R × T to determine the osmotic pressure.

Step-by-step explanation:

To make an intravenous saline solution that matches the osmotic pressure of red blood cells, you need to calculate the molarity of NaCl needed in the solution. When 1 mol of NaCl dissociates, it produces 2 mol of solute particles. The total concentration of dissolved particles should be 1.4 M to match the osmotic pressure. Using the equation Osmotic Pressure = Molarity × R × T, you can calculate the osmotic pressure of the solution.