Question

An organ pipe that is open at both ends has a fundamental frequency of 382 Hz. What is the length of a closed-end pipe that has a fundamental frequency exactly one octave higher?

Answer 1

382 Hz = v / 2L

v = 382 Hz * 2L

v = 764 Hz * 4L

v = 3056 Hz * L

L = v / 3056 Hz

L = 343 m/s / 3056 Hz

L = 0.246 m

Therefore, the length of the closed-end pipe is 0.246 m.